sym, symfun, and function handle

1 view (last 30 days)
Hoang Minh Le
Hoang Minh Le on 20 Dec 2022
Answered: Rohit on 11 Jan 2023
syms y1(x) y2
y1(x) = x^2 % symfun
y2 = x^2 % sym
y3 = @(x) x^2 % function handle
I am on day 1 of learning symbolic toolbox.
My question is about how to use the functions above appropriately.
My understandings so far:
  • Between y1 and y2, I understand that y2 needs sub() to evaluate.
  • (Answered somewhere on the forum) y3 has better excute time for numeric substitution

Accepted Answer

Rohit
Rohit on 11 Jan 2023
Hello,
In order to better understand the use of these functions, I am sharing the documentation of “sym”, function handles and the documentation link for symbolic Math Toolbox which contain examples to help you get started. Below are the links for the same:

More Answers (0)

Tags

Products


Release

R2021b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!