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How do I exit a for loop after logical index is found true in an array?

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I would like to exit a loop if the result is set to true in the for loop. But it always returns false if I use 'continue'. How do I resolve this?
% check if trajectory goes through the zone
result = false;
for i = 1:length(xNormalized)
if (xNormalized(i) > xEdge(1) && xNormalized(i) < xEdge(2)) && ...
(yNormalized(i) > yEdge(1) && yNormalized(i) < yEdge(2))
result = true;
end
% continue;
end

Accepted Answer

VBBV
VBBV on 4 Dec 2022
use inside the if-end statement
% check if trajectory goes through the zone
result = false;
for i = 1:length(xNormalized)
if (xNormalized(i) > xEdge(1) && xNormalized(i) < xEdge(2)) && ...
(yNormalized(i) > yEdge(1) && yNormalized(i) < yEdge(2))
result = true
break % use inside the if - condition
end
end
  2 Comments
VBBV
VBBV on 4 Dec 2022
Edited: VBBV on 4 Dec 2022
If you use outside the if condition the result state may not be saved to true if this for loop is nested inside another loop which means it will restore the result state back to false. I presume, this for loop is present inside another loop, thats why result flag is being set to false again.
If you want to avoid reuslt to set false, you need to place the result flag outside of all nested loops.
Struggling in MATLAB
Struggling in MATLAB on 4 Dec 2022
Thank you! I was using outside the if statement and that did not work. It works if I use inside if as you suggested. By the way, this for loop is the outermost loop.

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More Answers (1)

Steven Lord
Steven Lord on 4 Dec 2022
continue exits the current iteration and proceeds to the next iteration.
break exits the loop entirely.

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