Error using scatteredInterpolant on missing data
13 views (last 30 days)
Show older comments
Hello everyone,
I would like to use function scatteredInterpolant or interp1 to compare results with fillmissing function and inpaint_nans on the leading or trailing missing values (NaN)/ peak at the edge as attached file.
However, it has this error when I tried to input the data. I tried to read some instruction on MATLAB, but my data, it does not have any functions of x and y for z. Could anyone please help me figure out the reason to input the data properly?.
Thank you very much!
T = readtable ('data.csv')
data = table2array(T) ;
x = data(1,:) ; x(1) = [] ;
y = data(:,1) ; y(1) = [] ;
z = data(2:end,2:end) ;
F = scatteredInterpolant(x,y,z)
Error using scatteredInterpolant
The input points must be specified in column-vector format.
0 Comments
Accepted Answer
Cris LaPierre
on 22 Nov 2022
When using the syntax F = scatteredInterpolant(x,y,v), your inputs must all be vectors. That means v=z(:), and that x and y are the same length as v. Try something like this.
T = readtable ('https://www.mathworks.com/matlabcentral/answers/uploaded_files/1203033/data.csv');
data = table2array(T) ;
x = data(1,:) ; x(1) = [] ;
y = data(:,1) ; y(1) = [] ;
z = data(2:end,2:end) ;
[X,Y] = meshgrid(x,y);
F = scatteredInterpolant(X(:),Y(:),z(:))
% visualize the result
[xq,yq] = meshgrid(linspace(400,450),linspace(150,200));
vq = F(xq,yq);
plot3(X(:),Y(:),z(:),'b.',xq,yq,vq,'r.')
More Answers (1)
Kai
on 22 Nov 2022
Hi Ngoc, so for the scatteredInterpolant function, it's goal is to get the interpolant based on given x y z coordinates and the corresponding values on these coordinates. Based on your csv file, I am assuming you are trying to interpolate 2D data. In this case will be F = scatteredInterpolant (x,y,v), which the function itself is trying to get the F in v = F(x,y). After F is calculated, you can bring in the sampled point coordinate (x_s,y_s) in to F(x_s,y_s) to get the interpolate values.
As for the column-vector error, the scatteredInterpolant’s input data must be in sizes of m x 1, you can use transpose or reshape to change it into column-vector format to solve the error.
Also based on your code, you only extracted the values of x and y, but didn't match them into coordinate (x,y), and that is why the size of x and y arrays are different. I will recommend checking this example in the link and specifically the size differences of the sample array used in it: 2D interpolant sample
See Also
Categories
Find more on Time Series Events in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!