converting vector result into matrices for surf command

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Hello,in a program there is feald on aplane shown bellow.
the field data was exports and i am trying to recreate this fiels in matlab.
I have a problem where the exported tablable is show in the attached file ,the resulthas a vector as a result.
in surf command i needthe IMAGEEy result be a matrix
its folding every 24 members.
how can i recreate the photo of the progrm thanks?
I tried the photo shown bellow and it gave me gibrish
rows=(with.zmm==48.394400000000000);
data=with(rows,:);
x=data.xmm(1:24);
y=data.ymm;
y2=y(1:24:240);
z=reshape(data.EyImVm,24,[]);
[yy,xx]=meshgrid(x,y2)
surf(xx',yy',z)

Answers (2)

Walter Roberson
Walter Roberson on 20 Nov 2022
filename = 'https://www.mathworks.com/matlabcentral/answers/uploaded_files/1200898/with.txt';
with = readtable(filename);
with.Properties.VariableNames = {'xmm', 'ymm', 'zmm', 'ExReVm', 'ExImVm', 'EyReVm', 'EyImVm', 'EzReVm', 'EzImVm'};
rows = ismembertol(with.zmm,48.394400000000000);
data = with(rows,:);
x = data.xmm(1:24);
y = data.ymm;
y2 = y(1:24:240);
z = reshape(data.EyImVm,24,[]);
[yy, xx] = meshgrid(x, y2);
surf(xx',yy',z)
xlabel('x'); ylabel('y'); zlabel('EyImVm');
  1 Comment
fima v
fima v on 21 Nov 2022
Hello i ineed to plot the Z-X surface data at Y=-11.340800000000000
how can wec cut in this plane?
Thanks.

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Star Strider
Star Strider on 20 Nov 2022
I have no idea what you want to plot.
Use the first two column (that correspond to ‘x’ and ‘y’ respectively), the choose whatever other column you want, and use scatter3 to plot them. m There is no need to reshape them.
T1 = readtable('https://www.mathworks.com/matlabcentral/answers/uploaded_files/1200898/with.txt')
T1 = 10560×9 table
Var1 Var2 Var3 Var4 Var5 Var6 Var7 Var8 Var9 _______ _______ ______ ________ ________ _______ _______ _________ ________ -48.384 -11.341 10.996 0.90813 1.8604 -37.911 -79.726 -2.0314 -3.5672 -46.047 -11.341 10.996 0.61978 1.2805 -36.158 -76.018 -0.69598 -0.80282 -43.709 -11.341 10.996 0.39263 0.83229 -35.522 -74.668 0.27129 1.1548 -41.372 -11.341 10.996 0.83176 1.7557 -35.755 -75.141 0.99512 2.5929 -39.034 -11.341 10.996 0.13691 0.29173 -35.001 -73.53 2.5863 5.8309 -36.697 -11.341 10.996 -0.57036 -1.1999 -35.671 -74.939 1.8947 4.2114 -34.36 -11.341 10.996 -0.98216 -2.0772 -39.062 -82.094 -1.6248 -3.4085 -32.022 -11.341 10.996 -1.0985 -2.3401 -45.176 -94.994 -7.9721 -17.029 -29.685 -11.341 10.996 3.0031 6.3116 -48.701 -102.43 -9.4638 -20.382 -27.348 -11.341 10.996 2.4817 5.2283 -41.237 -86.694 -3.1886 -7.3027 -25.01 -11.341 10.996 1.1922 2.5145 -36.242 -76.16 1.4338 2.3349 -22.673 -11.341 10.996 0.22708 0.4812 -34.936 -73.407 2.2261 3.9499 -20.335 -11.341 10.996 -0.32721 -0.67962 -34.818 -73.17 1.827 3.1152 -17.998 -11.341 10.996 -0.41435 -0.88218 -34.896 -73.346 1.5551 2.6268 -15.661 -11.341 10.996 -0.51603 -1.11 -35.857 -75.404 0.60022 0.71022 -13.323 -11.341 10.996 -0.41121 -0.89323 -37.957 -79.868 -0.086691 -0.62588
x = T1{:,1};
y = T1{:,2};
z = T1{:,3};
Eyv = T1{:,6};
figure
scatter3(x, y, z, 10, z, 'filled')
grid on
colormap(turbo)
view(30,20)
figure
scatter3(x, y, Eyv, 10, Eyv, 'filled')
grid on
colormap(turbo)
view(30,20)
Experiment to get the desired result.
.
  6 Comments
Walter Roberson
Walter Roberson on 22 Nov 2022
A line, maybe? Constant z and constant y over a source that is a grid of data would still leave open the possibility of a line graph, EyImVm vs x ?
Star Strider
Star Strider on 22 Nov 2022
Certainly! Although some sort of scatter plot is at the base of this. The surface — if one exists — evolves from that. I just don’t understand how to get there from the provided data.

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