关于相控阵工具箱中phased.FreeSpace模块中计算自由空间传输损耗的疑问
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在phased.FreeSpace的帮助文档中写道:
When the origin and destination are stationary relative to each other, you can write the output signal of a free-space channel as Y(t) = x(t-τ)/Lfsp. The quantity τ is the signal delay and Lfsp is the free-space path loss. The delay τ is given by R/c, where R is the propagation distance and c is the propagation speed. The free-space path loss is given by

这里给出了单程传输过程中的信号幅度是反比于
,如果是双程传输,则应该再乘以一次单程传输损耗。因此,信号幅度的损失是反比于
。但是雷达方程中给出,双程传输过程中,接收信号的功率是反比于
。根据功率是幅度的平方,所以双程传输接收信号幅度应该是反比于
。这与帮助文档中给出的结论矛盾。
请问,是我理解的有问题,还是该模块算法有错误?还请各位大佬帮忙解答一下,不胜感激!
2 Comments
Jun
on 23 Jan 2024
您好,我也是这样想的。另外想请教一下您对这个历程怎么看,信号幅度的处理好办,但是为什么历程的1变成复数了,我不太清楚这里
mage bryan
on 23 Jan 2024
Answers (0)
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