How can i extract the numbers from string?

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Im trying to extract the numbers from a cell array? How can i do this?
cell array:
filename =
1×12 cell array
Columns 1 through 4
{'104p8.png'} {'105.png'} {'105p2.png'} {'105p4.png'}
Columns 5 through 8
{'105p6.png'} {'105p8.png'} {'106.png'} {'106p2.png'}
Columns 9 through 12
{'106p4.png'} {'106p6.png'} {'106p8.png'} {'107.png'}
Thanks
  4 Comments
Happy PhD
Happy PhD on 7 Nov 2022
I expect to return the value: 104.8
p is '.'
Marcel
Marcel on 7 Nov 2022
you might wanna update you question with this information

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Accepted Answer

Stephen23
Stephen23 on 7 Nov 2022
Edited: Stephen23 on 7 Nov 2022
Here are two approaches:
C = {'104p8.png','105.png','105p2.png','105p4.png','105p6.png','105p8.png','106.png','106p2.png','106p4.png','106p6.png','106p8.png','107.png'}
C = 1×12 cell array
{'104p8.png'} {'105.png'} {'105p2.png'} {'105p4.png'} {'105p6.png'} {'105p8.png'} {'106.png'} {'106p2.png'} {'106p4.png'} {'106p6.png'} {'106p8.png'} {'107.png'}
V = str2double(strrep(strrep(C,'.png',''),'p','.'))
V = 1×12
104.8000 105.0000 105.2000 105.4000 105.6000 105.8000 106.0000 106.2000 106.4000 106.6000 106.8000 107.0000
V = str2double(regexprep(C,{'\.png$','p'},{'','.'},'ignorecase')) % more robust
V = 1×12
104.8000 105.0000 105.2000 105.4000 105.6000 105.8000 106.0000 106.2000 106.4000 106.6000 106.8000 107.0000

More Answers (1)

Marcel
Marcel on 7 Nov 2022
Edited: Marcel on 7 Nov 2022
Hi i made a test script and came up with the following code. I found a solution here
example = cellstr(["1024.png", "image1003.png", "photo-1234.png"])
for i=1:length(example)
name = example{i};
numbers = str2double(extract(name, digitsPattern))
end
example =
1×3 cell array
{'1024.png'} {'image1003.png'} {'photo-1234.png'}
numbers =
1024
numbers =
1003
numbers =
1234

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