Clear Filters
Clear Filters

Why loop is not being excluded with the given condition?

2 views (last 30 days)
I am using the continue function to exclude the nodes of a sine function in matlab. When I start from 0, it is excluding all the nodes. However, when I start from 0.1 (for some reasons), it does not exclude the nodes i.e. 1.5, 2.5, 3, 3.5. Can you tell me what can be the reason and how to deal with it?
F_b = 16000; % N
A_b = 125.66; % mm^2
for cycles = 0:0.1:10
if cycles/0.5 == fix(cycles/0.5)
continue
end
disp(cycles)
end
0.1000 0.2000 0.3000 0.4000 0.6000 0.7000 0.8000 0.9000 1.1000 1.2000 1.3000 1.4000 1.6000 1.7000 1.8000 1.9000 2.1000 2.2000 2.3000 2.4000 2.6000 2.7000 2.8000 2.9000 3.1000 3.2000 3.3000 3.4000 3.6000 3.7000 3.8000 3.9000 4.1000 4.2000 4.3000 4.4000 4.6000 4.7000 4.8000 4.9000 5.1000 5.2000 5.3000 5.4000 5.6000 5.7000 5.8000 5.9000 6.1000 6.2000 6.3000 6.4000 6.6000 6.7000 6.8000 6.9000 7.1000 7.2000 7.3000 7.4000 7.6000 7.7000 7.8000 7.9000 8.1000 8.2000 8.3000 8.4000 8.6000 8.7000 8.8000 8.9000 9.1000 9.2000 9.3000 9.4000 9.6000 9.7000 9.8000 9.9000
The other is
F_b = 16000; % N
A_b = 125.66; % mm^2
for cycles = 0.1:0.1:10
if cycles/0.5 == fix(cycles/0.5)
continue
end
disp(cycles)
end
0.1000 0.2000 0.3000 0.4000 0.6000 0.7000 0.8000 0.9000 1.1000 1.2000 1.3000 1.4000 1.5000 1.6000 1.7000 1.8000 1.9000 2.1000 2.2000 2.3000 2.4000 2.5000 2.6000 2.7000 2.8000 2.9000 3.0000 3.1000 3.2000 3.3000 3.4000 3.5000 3.6000 3.7000 3.8000 3.9000 4.1000 4.2000 4.3000 4.4000 4.6000 4.7000 4.8000 4.9000 5.1000 5.2000 5.3000 5.4000 5.6000 5.7000 5.8000 5.9000 6.1000 6.2000 6.3000 6.4000 6.6000 6.7000 6.8000 6.9000 7.1000 7.2000 7.3000 7.4000 7.6000 7.7000 7.8000 7.9000 8.1000 8.2000 8.3000 8.4000 8.6000 8.7000 8.8000 8.9000 9.1000 9.2000 9.3000 9.4000 9.6000 9.7000 9.8000 9.9000
Thanks for the help in advance.
Regards,
Muhammad Hassaan Bin Tariq
  2 Comments
Stephen23
Stephen23 on 18 Oct 2022
"Can you tell me what can be the reason..."
Because 0.1 cannot be exactly stored in a binary floating point number (in exactly the same way that you cannot write 1/3 exactly on a piece of paper using a decimal fraction). The floating point error accumulates differently in the COLON operator, depending on the provided values. Lets compare:
cycles0 = 0:0.1:10;
cycles1 = 0.1:0.1:10;
fprintf('%.40f\n', cycles0(16)/0.5, fix(cycles0(16)/0.5), cycles1(15)/0.5, fix(cycles1(15)/0.5))
3.0000000000000000000000000000000000000000 3.0000000000000000000000000000000000000000 3.0000000000000004440892098500626161694527 3.0000000000000000000000000000000000000000
"...and how to deal with it?"
Either:
  • work with integers, or
  • use tolerances when comparing (i.e. do not use exact equality), avoid FIX, etc.
Your current approach is numerically fragile and should be avoided.
Muhammad Hassaan Bin Tariq
I got your point but why is it avoiding higher points with the same fix command? I mean it is excluding 7, 7.5, 8 etc.
It is a long code. Well the mod() operation is working well.
Thanks for your help very much.
Regards

Sign in to comment.

Accepted Answer

Tobias Panitz
Tobias Panitz on 18 Oct 2022
Hey,
have you tried using the modulus function?
if mod(cycles,0.5) == 0
continue;
end

More Answers (0)

Categories

Find more on Loops and Conditional Statements in Help Center and File Exchange

Products


Release

R2022a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!