Repetition and Discontinuity Function

I want to create a function that evaluates:

 v = 1/3.190e9*(800x^3 - 13.68e6x - 2.5x^4 + 2.5<x-120>^4 + 600<x-240<^3) 

 <x-a>^n = (x-a)^n if x>=a and 0 if x<a

The user would input an array like [0:.5:360]

[Geoff Hayes]

Jorge - what does the syntax

 <x-20>

mean to you? What about

 600<x-240<^3

Is there a typo in the above or does it have some particular meaning?

[Image Analyst]

Also, what does 13.68e6x mean? How about 13.68 * 10^(6*x) or maybe 13.68 * exp(6*x)?

Answer 1

[Image Analyst]

How about

function test
x = [0:.5:360];
a = 10;  % Whatever...
v = vx(x, a)  % Call the vx function.

function v = vx(x, a)
x(x<a) = 0;
v = (1/3.190e9) * 800 * x .^ 3 - ...
    13.68 * 10 .^ (6 * x) - ...
    2.5 * x .^ 4 + ...
    2.5 * (x - 120) .^ 4 + ...
    600 * (x - 240) .^ 3;