- You need to use size , not numel to get the size of the array in one dimension. Use size's second dimension option to specify which dimension you want to measure.
- You concatenate the NaN-padding using square brackets to join them horizontally [x,nan(..)]. Square brackets can concatenate only along the first or second dimension (i.e. [x;y] and [x,y] respectively), but you require the third dimension (because this is where your arrays have different sizes). For this you can use padarray.
cell2array with different dimension cells.....
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my cellarray is 1x4....
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/147240/image.png)
I want to convert it into array... but dimensions are different for last cell...
For that, i was tried this code...
maxSize = max(cellfun(@numel,imgData)); %# Get the maximum vector size
fcn = @(x) [x, nan(1,maxSize-numel(x))]; %# Create an anonymous function
rmat = cellfun(fcn,imgData,'UniformOutput',false); %# Pad each cell with NaNs
rmat = vertcat(rmat{:}) %# Vertically concatenate cells
and it show me error !!
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/147241/image.png)
so, any solution for this problem... Thank you in advance...
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Accepted Answer
Stephen23
on 22 Feb 2015
Edited: Stephen23
on 22 Feb 2015
There are a couple of issues here
As an alternative, you could use cat to concatenate them in the dimension that they are different (e.g. the third in your example). This does not require adding the NaN's, so you need to decide what is best for your situation.
cat(3,imgData{:})
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