N=zeros(1,3);
for i=1:243
if a(3*i)=='C'
N(1)=N(1)+1;
elseif a(3*i)=='G'
N(2)=N(2)+1;
elseif a(3*i)=='C'| a(3*i)=='G' %这个地方运行不出结果,改为 elseif a(3*i)=='C'| 'G'后出结果,但是应该不对
N(3)=N(3)+1;
end
end
a是729个由A、C、G、T组成的字符串,目的是计算第3、6、9、12(三的倍数)出现C、G、C或G的数目。
敬请大神指点

 Accepted Answer

大子 胆
大子 胆 on 10 Jul 2022

0 votes

a(3*i)=='C'| a(3*i)=='G'
修改为
isequal( a(3*i), 'C' ) || isequal( a(3*i), 'G' )
试试

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