Help with For-Loop question?
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I keep getting the same error, about not being any real or logical answer.
here is the question; Create a time vector x = 0:2*pi. Using a for-loop, plot ten different curves on the same graph where the first curve is x1 = sin(x), the second curve is x2 = sin(x1), the third curve is x3 = sin(x2) and so on. Note that by using a for-loop it is not necessary to create ten separate variables to solve this problem.
Here is what I've been entering
x=0
>> for i=[pi/5:pi/5:2*pi]
x(i)=sin(x(i-(pi/5)))
end
??? Attempted to access x(0); index must be a positive integer or logical.
Any help would be appreciated
1 Comment
Walter Roberson
on 5 Oct 2011
Duplicate is at http://www.mathworks.com/matlabcentral/answers/17480-help-with-for-loop-question
Accepted Answer
More Answers (1)
Fangjun Jiang
on 5 Oct 2011
When you use i=[pi/5:pi/5:2*pi], i is a vector with increment as pi/5, hardly any of the element is integer, you can not use i as the index of a vector as x(i). Try something like,
N=10;
x=zeros(N,1);
for k=1:N
a=k*pi/5;
x(k)=sin(a);
end
i is the square root of -1 so avoid using i. Try this:
clear i
i
4 Comments
Abdullah Tamimi
on 5 Oct 2011
Sean de Wolski
on 5 Oct 2011
it's preallocating for speed. You create the full vector at once, the size you need it, and then populate it as the for loop runs.
Sean de Wolski
on 5 Oct 2011
for your own knowledge, you should just type it at the command line and see what it creates
Fangjun Jiang
on 5 Oct 2011
Without the x=zeros(N,1) ahead of the for-loop, the code still works. It's just the vector x will increase size at every loop. This is not efficient especially when N is large, as MATLAB likes to store vector or matrix in a continuous memory location.
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