"Column Vector" XTick labels

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Mark Stone
Mark Stone on 28 May 2022
Commented: dpb on 30 May 2022
Consider the following plot:
plot(0:2,2-(0:2),'*'),xticks([0 1 2]),xticklabels({'(0,2)','(1,1}','(2,0)'})
I want to keep the "plot" as is, just change the labeling for the x axis ticks., so that each xtick label would be a column vector instead of a pair in parentheses. For instance,
0 1 2
2 1 0
instead of
(0,2) (1,1) (2,0)
Is this possible?

Accepted Answer

Voss
Voss on 28 May 2022
Edited: Voss on 28 May 2022
plot(0:2,2-(0:2),'*')
xticks([0 1 2])
xticklabels(sprintfc('%d\\newline%d',[0 2 1 1 2 0]))
  5 Comments
dpb
dpb on 30 May 2022
I guess I had never looked that up before, or if had done in the past, had certainly forgotten it.
The undocumented sprintfc is handy, too; that replaces the functionality I got with the loop and explicit cast. I hadn't stumbled over it before, either...

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More Answers (1)

dpb
dpb on 28 May 2022
Edited: dpb on 28 May 2022
I don't think so with the tick labels(*), but you can write them with text as
v1=[0:2];v2=[2:-1:0];
for i=1:3
xtl(i)=cellstr(sprintf('%d\n%d',v1(i),v2(i)));
end
xticklabels([])
text(xticks,repmat(-0.02,1,3),xtl,'VerticalAlignment',"top")
(*) When try to write string with embedded \n, the internals of xticklabels converts each to another string element so you end up with it thinking 2X the labels than number of ticks.
  2 Comments
dpb
dpb on 28 May 2022
Yeah, it is "magic" number as shown -- because the default coordinates for text are in 'data' units. This can be set to be 'normalized' which are the units of the axes and then a fixed offset from the lower position number is the invariant way to place.

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