# Divide each column by the sum of the column in a matrix

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I am sure this is an elementary question, but I could not find the answer when searching the Matlab website. I was wondering how to divide each column in a matrix by the sum of that column and do the same process for all the columns in a matrix. The result should then be returned as a new matrix.

As an example take the following matrix

D = [-0.442898926677253 -0.165258150390309 0.850111606631490 -0.801783725737275;

-0.505610279127129 0.455832504673115 -0.205467096352270 4.76435784320108e-15;

-0.540885414880185 -0.746406858955920 -0.439177413926944 0.534522483824847;

-0.505610279127129 0.455832504673115 -0.205467096352275 0.267261241912423];

Now, for the first column;

U(:,1)/sum(U(:,1))

gets the first column of D divided by the sum of the column, but how do I do this for all of the columns and return the output as a new matrix?

##### 2 Comments

Matt J
on 19 May 2022

U(:,1)/sum(U(:,1)) gets the first column of D divided by the sum of the column

No, it does that for U, not D.

### Accepted Answer

Matt J
on 19 May 2022

D./sum(D)

##### 6 Comments

Torsten
on 19 May 2022

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