3D plot using time series

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Ieuan Price-davies
Ieuan Price-davies on 27 Apr 2022
Commented: Star Strider on 27 Apr 2022
I'm trying to create a 3D graph like the image below. I have attached a reduced data set of my results below. Does anyone know how this would work?
I've currently tried surf and waterfall but I can't seem to get it working. It a mess but this is kind of what I've been working with
results.
In effect I want each day of the results to be shown on a different "slice"
%Sets Date time format for when table is read
opts = detectImportOptions("results.xlsx","Sheet","Sheet1");
opts = setvartype(opts,"Date","datetime");
opts = setvaropts(opts,"Date",'InputFormat','dd.MM. HH:mm');
results = readtable("results.xlsx",opts);
x = results.Efficiency;
y = results.Power;
% z = results.Date; % HOW DO YOU INCLUDE THIS?
[X,Y] = meshgrid(x,y);
Z = peaks(X,Y);
waterfall(X,Y,Z)

Accepted Answer

Star Strider
Star Strider on 27 Apr 2022
results = readtable('https://www.mathworks.com/matlabcentral/answers/uploaded_files/980365/results.xlsx', 'VariableNamingRule','preserve');
results.Date = datetime(results.Date, 'InputFormat','MM.dd. HH:mm', 'Format','MM.dd. HH:mm')
results = 30×15 table
Date AmbientTemp SkyTemp GlassTemp PVTemp AbsorberTemp Irradiance WindSpeed Power WaterTemp WaterTemp2 Efficiency Hwind Kair Pb ____________ ___________ _______ _________ ______ ____________ __________ _________ ______ _________ __________ __________ ______ _____ _______ 01.01. 00:00 300.3 287.26 287.26 286.89 286.5 0 3.7 0 0 289.95 0.19869 19.952 300.3 -1200 01.01. 01:00 299.5 286.11 286.11 285.77 285.41 0 3.2 0 0 289.43 0.19878 18.022 299.5 -1200 01.01. 02:00 298.6 284.82 284.82 284.35 283.85 0 4.8 0 0 288.68 0.19889 24.198 298.6 -1200 01.01. 03:00 299.3 285.82 285.82 285.31 284.77 0 5.5 0 0 289.12 0.19881 26.9 299.3 -1200 01.01. 04:00 298.8 285.11 285.11 284.62 284.1 0 5.1 0 0 288.8 0.19887 25.356 298.8 -1200 01.01. 05:00 299.1 285.54 285.54 285.13 284.71 0 4 0 0 289.09 0.19883 21.11 299.1 -1200 01.01. 06:00 299.1 285.54 285.86 285.47 285.04 12.9 4 2.5645 0 289.25 0.1988 21.11 299.1 -1197.4 01.01. 07:00 300 286.83 293.07 292.88 292.43 259 4.2 51.337 0 292.78 0.19821 21.882 300 -1148.7 01.01. 08:00 300.9 288.12 299.65 299.66 299.18 498 4.2 98.443 0 296 0.19768 21.882 300.9 -1101.6 01.01. 09:00 301.6 289.13 303.02 303.13 302.63 614 4.2 121.2 0 297.65 0.1974 21.882 301.6 -1078.8 01.01. 10:00 302.5 290.42 311.37 311.75 311.19 972 4.4 191.21 0 301.74 0.19672 22.654 302.5 -1008.8 01.01. 11:00 302.8 290.85 306.95 307.17 306.67 732 4.8 144.26 0 299.58 0.19708 24.198 302.8 -1055.7 01.01. 12:00 303 291.14 308.95 309.22 308.71 819 4.6 161.28 0 300.55 0.19692 23.426 303 -1038.7 01.01. 13:00 303.1 291.28 306.04 306.2 305.72 669 4.8 131.9 0 299.12 0.19716 24.198 303.1 -1068.1 01.01. 14:00 303 291.14 304.11 304.2 303.73 582 4.6 114.84 0 298.18 0.19732 23.426 303 -1085.2 01.01. 15:00 302.4 290.28 296.13 295.9 295.41 251 5.9 49.691 0 294.2 0.19797 28.444 302.4 -1150.3
x = results.Efficiency;
y = results.Power;
z = results.AmbientTemp;
xv = linspace(min(x), max(x), numel(x)); % Create Vector For Interpolation
yv = linspace(min(y), max(y), numel(y)); % Create Vector For Interpolation
[X,Y] = ndgrid(xv,yv); % Create Matrices For Interpolation
Z = griddata(x, y, z, X, Y); % Interpolate Matrix
figure
stem3(x, y, z, 'p', 'filled')
grid on
title('Stem Plot')
figure
surfc(X, Y, Z)
grid on
xlabel('Efficiency')
ylabel('Power')
zlabel('Temperature [°C]')
title('Surface Plot')
Experiment with this approach with your actual data.
.
  4 Comments
Ieuan Price-davies
Ieuan Price-davies on 27 Apr 2022
Thank you Star Strider that's amazing!
Star Strider
Star Strider on 27 Apr 2022
As always, my pleasure!
To create different surface plots, change the ‘x’ and ‘y’ variables in my code to be the independent variables for the plot, and then use the appropriate ‘z’ vector in the griddata call. The code should be relatively robust to those changes.

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