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Using a user defined fucntion with blockproc

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Jason on 15 Jan 2015
Commented: Jason on 15 Jan 2015
Is there a mistake in my syntax using blocproc:
Binary1=blockproc(OrigImage,[tileRowSize, tileColSize],@(x) myOperation(hObject, eventdata, handles,;
the function I use "myOperation" is as follows:
function myOperation(hObject, eventdata, handles,tile)
[thresh1, thresh2] = Threshold(hObject, eventdata, handles,tile); %my personal thresholding function
%Create Binary Image
Im getting
Binary1 =

Answers (2)

Image Analyst
Image Analyst on 15 Jan 2015
I don't have time to look at it now, but in the meantime, see my blockproc demos, attached.

Iain on 15 Jan 2015
What does your "myfunction" function output? It looks like it's not producing any output.
Image Analyst
Image Analyst on 15 Jan 2015
If you have blocks of 25 pixels by 25 pixels, and you move in "jumps" of 25 pixels, then I believe your last block will have only 1 row or column. Thus it may not have a value like the others that had a full block in them.
Jason on 15 Jan 2015
Yes that makes sense.
Is it possible to return also the mean intensity of each sub image using blockproc, I thought I could just add an extra output variable from my function such as:
function [BI, mn] = myOperation(hObject, eventdata, handles,tile)
%then the rest of the code.
and then obtain a matrix of mean values via:
[Binary1, mn]=blockproc(OrigImage,[tileRowSize, tileColSize],@(x) myOperation(hObject, eventdata, handles,;
But it complains about too many output arguments for Blockproc.

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