Removing multiple columns from a matrix

I have a data matrix a = 630x3000, and I want to delete the first few columns based on length of another matrix that holds the number of columns i need to delete for each row, b = 630x1.

For example for the first row (1x3000), I need to delete 0 columns , but the next row (2x3000), I need to delete 6 columns. I would then like to pad zeroes onto the end of the matrix based on how many column I removed. This is to ensure the matrix stays the same size.

I understand how to delete indiviudal columns, but I am not sure how to implement this in a loop based on a changing value.

I believe it is something like this, but it is only removing that column number instead of the first 6, etc...

for i = height(a)

a[:b(i)] = []

a =[a(i) zeros(1,b(i))]

end

Answer 1

[Jon]

I think this will do what you want

for k = 1:numel(b)
    a(k,:) = [a(k,b(k)+1:end),zeros(1,b(k))]
end