loop of Column Average

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Arvind Gauns
Arvind Gauns on 19 Apr 2022
Commented: Arvind Gauns on 19 Apr 2022
I have a matrix of 1024 * 78.(datatype: double )
I want to average every two columns such that the resultant matrix must be 1024*39. (average of every two matrix)
how to get it done?
again for time being if i dont know the number of columns (due to huge dataset) and want to run a loop for averaging the columns for the similar case as mentioned about, what will be the changes in the code ?

Accepted Answer

Davide Masiello
Davide Masiello on 19 Apr 2022
Edited: Davide Masiello on 19 Apr 2022
There's no need to use a for loop.
Try the code below.
clear,clc
A = rand(1024,78); % initial matrix of doubles
B = (A(:,1:2:end-1)+A(:,2:2:end))/2; % matrix of averages for each two columns
size(B)
ans = 1×2
1024 39

More Answers (1)

Eric Delgado
Eric Delgado on 19 Apr 2022
Hi @Arvind Gauns, just pass your input matrix to the function below. Hope it helps! :)
function outMatrix = Fcn_twoColumnsMean(inMatrix)
arguments
inMatrix (1024,:) {mustBeNumeric} = randn(1024, 78)
end
NN = floor(width(inMatrix)/2);
outMatrix = zeros(1024, NN);
for ii = 1:NN
outMatrix(:,ii) = mean(inMatrix(:,2*ii-1:2*ii), 2);
end
end
  5 Comments
Eric Delgado
Eric Delgado on 19 Apr 2022
For sure! Especially if the script is becoming too big. So... you have to create modules for debugging purposes. But at the end of the day, it's your call! :)
Arvind Gauns
Arvind Gauns on 19 Apr 2022
in that case i need not need to call the function right ?

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