Clear Filters
Clear Filters

heat equation for infinite bar(rod)

2 views (last 30 days)
Nicoleta
Nicoleta on 8 Jan 2015
Commented: Torsten on 9 Jan 2015
%Ecuatia caldurii pt bara infinita function ec_cald_bara_infin a=0;b=50;L=10;T=15;Ns=20;M=50;N=50;t=linspace(0,T,50); x=linspace(0,10,50); c=linspace(a,10,b); s=linspace(0,10,50); %calcul Y for n=1:N for m=1:M
Y=f(s).*exp(-( x(n)-s).^2/(4*a*a*t(m))); y=f(s); l=length(y) z=exp(-( x(n)-s).^2/(4*a*a*t(m))); p=length(z) D=Y.*z; r=length(c)
q=trapz(D,c);
%calcul u(t,n)
A=1/(2*a*sqrt(pi*t(m)));
w=length(A)
u(m,n)=A.*q;
end
end
figure(1) surf(t,x,u'); figure(2) for m=1:M plot(x,u(m,:))
axis([-L,L,min(min(u)), max(max(u))]);
film(m)=getframe; end movie(film,3,40); function f=f(s) f=s.*(L-s); end end
I tried figuring out this problem and all I managed to do is this code. Is it correct?
  1 Comment
Torsten
Torsten on 9 Jan 2015
I see the code, but from the title of your request, I can't deduce the problem.
Best wishes
Torsten.

Sign in to comment.

Answers (0)

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!