Filling an array with color points
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I am trying to create an array (matrix?)
I have J curves I am plotting and I want to create a vector of color values.
The matrix will have J rows and 3 entries per row. the First entry will be 0 the third entry will be 1. The second middle entry will be (i-1)*1./J. where i is my counter in the for loop.
```
j = 34; g = 3;
A = zeros(j,g);
for i= 1:j
A(:,i) = 0 (i-1)*1./j 1;
end
disp(A)
```
So I want something like, if j=34 , A=[0 0 1; 0 1/34 1; 0 2/34 1; ... ; 0 33/34 1;]
Thank you for your time and help.
Accepted Answer
Les Beckham
on 1 Apr 2022
Edited: Les Beckham
on 1 Apr 2022
j = 34; g = 3;
A = zeros(j,g);
A(:,3) = 1; % put ones in the third column
A(:,2) = ([0:j-1]/j).'; % fill in the second column (' makes it a column)
format rat
disp(A)
More Answers (1)
I think this is what you were going for:
j = 34; g = 3;
A = zeros(j,g);
for i= 1:j
A(i,:) = [0 (i-1)/j 1];
end
disp(A)
And you can do it without the loop like this:
A = [zeros(j,1) (0:j-1).'/j ones(j,1)];
disp(A)
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on 1 Apr 2022
on 1 Apr 2022
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