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Need help with If statement

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Aftab Ahmed Khan
Aftab Ahmed Khan on 31 Dec 2014
Edited: Jan on 31 Dec 2014
Hello everyone, My question is, in the below code, idsabs can take any value from 1 to 16. Depending on the value of idsabs, i want to set the value of idcabs. Is there any other way of doing this, because i think its too long just to get a single value. Thank you so much and Happy New Year.
if idsabs>=1 && idsabs<=2
idcabs=1;
elseif idsabs>=3 && idsabs<=4
idcabs=3;
elseif idsabs>=5 && idsabs<=6
idcabs=4;
elseif idsabs>=7 && idsabs<=8
idcabs=6;
elseif idsabs>=9 && idsabs<=10
idcabs=5;
elseif idsabs>=11 && idsabs<=12
idcabs=7;
elseif idsabs>=13 && idsabs<=14
idcabs=8;
elseif idsabs>=15 && idsabs<=16
idcabs=2;
end

  3 Comments

Stephen Cobeldick
Stephen Cobeldick on 31 Dec 2014
You define, for example, what happens for values of idsabs<=2 and idsabs>=3 , but what happens if idsabs is equal to 2.5 ?
Aftab Ahmed Khan
Aftab Ahmed Khan on 31 Dec 2014
Hi Stephen, idsabs will take only whole numbers between 1 to 16. No decimal values.
Jan
Jan on 31 Dec 2014
If you have checked for idsabs<=2, there is no reason to check "idsabs>=3" anymore.

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Accepted Answer

Stephen Cobeldick
Stephen Cobeldick on 31 Dec 2014
Edited: Stephen Cobeldick on 31 Dec 2014
If adsabs only has whole values, then you could simply use a look-up table:
vec = [1,3,4,6,5,7,8,2];
adcabs = vec(ceil(adsabs/2));
This produces exactly the same values for adcabs as your questions gives:
>> arrayfun(@(x) vec(ceil(x/2)), 1:16)
ans = [1 1 3 3 4 4 6 6 5 5 7 7 8 8 2 2]
If you can tell us something about how the order of adcabs was generated, then maybe we could come up with a small function instead.

  1 Comment

Aftab Ahmed Khan
Aftab Ahmed Khan on 31 Dec 2014
Thank you for your help. Its done.

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More Answers (1)

Jan
Jan on 31 Dec 2014
Edited: Jan on 31 Dec 2014
A little bit simpler without "compression" of the look-up-table:
LUT = [1, 1, 3, 3, 4, 4, 6, 6, 5, 5, 7, 7, 8, 8, 2, 2];
idcabs = LUT(idsabs);

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