If condition: "in each row of a matrix one element is zero and the other one is not zero"

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Sim
Sim on 29 Mar 2022
Commented: Sim on 6 Apr 2022
How can I write the
if condition
in a more compact way than
if size(find(sum(A==0,2)==1),1) == size(A,1)
to express that "in each row of my matrix one element is zero and the other one is not zero" ?
Here an example:
clc;
A = [ 1 0
0 9
12 0
0 2
0 3]
if size(find(sum(A==0,2)==1),1) == size(A,1)
disp('in each row one element is zero and the other one is not zero')
end

Accepted Answer

Voss
Voss on 29 Mar 2022
You can use all()
A = [ 1 0
0 9
12 0
0 2
0 3];
if all(sum(A==0,2) == 1)
disp('in each row one element is zero and the other one is not zero')
end
in each row one element is zero and the other one is not zero

More Answers (2)

Stephen23
Stephen23 on 29 Mar 2022
Edited: Stephen23 on 29 Mar 2022
A = [1,0;0,9;12,0;0,2;0,3]
A = 5×2
1 0 0 9 12 0 0 2 0 3
if any(A,2)&any(~A,2)
disp('in each row one element is zero and the other one is not zero')
end
in each row one element is zero and the other one is not zero
if diff(A==0,1,2) % this might be the most compact
disp('in each row one element is zero and the other one is not zero')
end
in each row one element is zero and the other one is not zero
A = [1,2;0,0;12,0;0,2;0,3]
A = 5×2
1 2 0 0 12 0 0 2 0 3
if any(A,2)&any(~A,2)
disp('in each row one element is zero and the other one is not zero')
else
disp('but not this one!')
end
but not this one!
if diff(A==0,1,2)
disp('in each row one element is zero and the other one is not zero')
else
disp('but not this one!')
end
but not this one!

Arif Hoq
Arif Hoq on 29 Mar 2022
Edited: Arif Hoq on 29 Mar 2022
try this
A = [ 1 0
0 9
12 0
0 2
0 3];
if nnz(A)==size(A,1)
disp('in each row one element is zero and the other one is not zero')
end
in each row one element is zero and the other one is not zero
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