How to split monthly value into days
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Hello everyone
I have a little issue here. Solution must be easy, but i cant figure it out.
I have 12 values (each represent ideal rain in every month) IR = [0 0 0 70 83 100 110 100 70 0 0 0]'
Then i have long datetime (10 years) with daily time step.
Need to find out value for each day.
Example: IR for 27.Sept = IR(Sept)/number of days in Sept
Thanks for every help
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Accepted Answer
Andrei Bobrov
on 27 Mar 2022
Let dates - your long datetime (10 years) with daily time step.
out = IR(month(dates))./day(dates,"dayofmonth")
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