why does the output show % when i type fprintf('%%')

 Accepted Answer

In the documentation section on formatSpec see the section on Text Before or After Formatting Operators.

4 Comments

r=99
fprintf('%d%%',r)
so when i type this i get 99%. So it's(%%) use is only to print or show percent
Yes.
The ‘%’ sign is a format operator for fprintf (and similar functions) so in order to print it as a percent sign, it must be ‘escaped’ by using .'%%'. Similarly, in order to print a ‘\’ it is necessary to ‘escape’ it as well '\\'. See the documentation section I linked to for a full discussion of all of them.
Sanjay N
Sanjay N on 17 Mar 2022
Edited: Sanjay N on 17 Mar 2022
Thank you
As always, my pleasure!

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