Replace string values in a table

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I have a column in a table with 3 wine types defined as character values "1", "2" and "3". I want to replace these values with "French", "Spanish" and "Italian" respectively. I am treating the column as an array of strings and using the tried and trusted combination of a for loop and if/elseif ladder to select and replace each of the string values in the table. Howver, when I run this in the command window, I get an error saying 'Unable to perform assignment because the left and right sides have a different number of elements' . My code is listed below and the array I am trying run it on is attached.
for i = 1:size(Typ)
if((Typ(i))=="1")
Typ(i)="French"
elseif((Typ(i))=="2")
Typ(i)="Spanish"
elseif((Typ(i))=="3")
Typ(i)="Italian"
else
end
end

Accepted Answer

Mathieu NOE
Mathieu NOE on 16 Mar 2022
hello
my 2 cents suggestion
Typ = readtable('Typ.csv');
Typ = table2array(Typ);
for i = 1:numel(Typ)
if((Typ(i))== 1)
newTyp{i,1}='French';
elseif((Typ(i))==2)
newTyp{i,1}='Spanish';
elseif((Typ(i))==3)
newTyp{i,1}='Italian';
else
end
end
Typ = newTyp;

More Answers (2)

Stephen23
Stephen23 on 16 Mar 2022
Edited: Stephen23 on 16 Mar 2022
The simple MATLAB approach would be to use indexing:
T = readtable('Typ.csv');
V = ["French";"Spanish";"Italian"];
T.Typ = V(T.V1)
T = 178×2 table
V1 Typ __ ________ 1 "French" 1 "French" 1 "French" 1 "French" 1 "French" 1 "French" 1 "French" 1 "French" 1 "French" 1 "French" 1 "French" 1 "French" 1 "French" 1 "French" 1 "French" 1 "French"

Eric Sofen
Eric Sofen on 17 Mar 2022
This is what categorical is built for! When you create the categorical, you can specify the data, value set, and category names.
T = readtable("https://www.mathworks.com/matlabcentral/answers/uploaded_files/929319/Typ.csv");
T.Typ = categorical(T.V1, 1:3, ["French", "Spanish","Italian"])
T = 178×2 table
V1 Typ __ ______ 1 French 1 French 1 French 1 French 1 French 1 French 1 French 1 French 1 French 1 French 1 French 1 French 1 French 1 French 1 French 1 French

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