Find if two elements are in a row of a matrix

I want to find two elements in A are also in B,and I would like to know B's index.

So the answer is 1 2 4 5 in B.

A=[1,3,7]
B=[1 8 3;
    1 2 3;
    3 4 5;
    1 7 9
    2 1 3];

This is what I tried.But clearly,it's not smart

find(B(:,1)==A(1,1)&B(:,2)==A(1,2))
find(B(:,1)==A(1,1)&B(:,3)==A(1,2))
find(B(:,2)==A(1,1)&B(:,3)==A(1,2))

(I can sort them and use ismember but it's still not intuitive. Any other function?)

[Matt J]

So the answer is 1 2 4 5 in B.

Why is that the answer?

[AI-CHI Chang]

Sorry not clear. I just put on part of my solution. It's because B's 1 2 4 5 row have two of elements in A

Answer 1

[Stephen23]

A = [1,3,7];
B = [1,8,3;1,2,3;3,4,5;1,7,9;2,1,3];
V = find(sum(ismember(B,A),2)==2)

V = 4×1

1 2 4 5

[AI-CHI Chang]

It is really helpful !! Thanks~