where is the mistake?
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function oo(w)
if isstring(w)
count =0;
while count<15
if strcmp(w(count),'r')
disp('yes')
count=count+1;
end
end
end
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Answers (2)
David Hill
on 25 Jan 2022
Why not just:
w='abcderfrgrhhr';
l=w=='r'
l =
1×13 logical array
0 0 0 0 0 1 0 1 0 1 0 0 1
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DGM
on 25 Jan 2022
Edited: DGM
on 25 Jan 2022
If you want it to do what your code implies:
w = 'a4jkltr6mramlkrffgajr';
oo(w)
function oo(w)
if isstring(w) % strings are not chars
w = char(w);
end
if ischar(w)
for c = 1:numel(w) % don't use a while loop, don't hard-code variable length
if w(c) == 'r' % don't need strcmp for single char tests
disp('yes') % if all you print is 'yes'
else
disp('no') % then there's no way to know where it occurred
end
end
end
end
If instead you want a function that's actually useful for something, @David Hill already posted a useful answer.
w = 'a4jkltr6mramlkrffgajr';
idx = letterisr(w)
function out = letterisr(w) % use a meaningful name and provide output
if isstring(w) % strings are not chars
w = char(w);
end
if ischar(w)
out = w == 'r';
end
end
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