Unstable Closed Loop Poles

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Brian Morey
Brian Morey on 13 Dec 2021
Answered: Net Fre on 13 Dec 2021
I have a plant transfer function gs which is stable on its own but the feedback loop is unstable because a pole appears on the right hand side of imaginary axis. How can I go about making system stable? I'm trying to make a controller similar to what's shown below with a lag compensator but I think I need to remove the unstable pole first.
gs = tf([-15.06 14.3 0.384], [1 2.383 8.791 0.2651 0.09111]) % plant transfer function
CLTF = feedback(gs,1) % results in closed loop poles that are unstable

Answers (1)

Net Fre
Net Fre on 13 Dec 2021
Using the rlocus function, you can see that up to a certain value of C (around 0.4 in your case) your closed loop will still be stable. Notice that the closer you get to that value your system will be closer to being unstable and will oscillate more.
Therefor you can start your controller design with a lower gain, such as:
CLgain = 0.25;
CLTF = feedback(CLgain*gs,1)
and try moving on from there.

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