Allocating values in a 3D array using nested for loops

I've created a 3D array (A) of zeros with dimensions : A=zeros(3,2,4). Using nested for loops I need to overwrite their values so the first value on the first page is 24, and all other values reduce by one each time.

Ex:

    A(:,:,1) 
    24 23 
    22 21 
    20 19 

    A(:,:,2)
    18 17 
    16 15 
    14 13

Other than pre-allocating A I have no idea where to start, any help would be appreciated.

Answer 1

[James Tursa]

Since this is apparently a homework assignment, I will get you started. Since the requirement is to use nested loops, I assume the instructor wants a loop for each index. So here is the outline, one loop for each index:

A=zeros(3,2,4);
for z = __:__
    for y = __:__
        for x = __:__
            A(x,y,z) = ____;
        end
    end
end

I will leave it to you to fill in the blanks.

Answer 2

[Azzi Abdelmalek]

A=permute(reshape(24:-1:1,2,3,4),[2 1 3])

[Blake Barrows]

Thanks for your help, but I need to accomplish this using nested for loops.

[Azzi Abdelmalek]

If it's a homework then try something yourself