Can you do this calculation any faster?

1 view (last 30 days)
Hi there
I am trying to optimize some code, an example is given below. In my code, v_ustar etc are calculated elsewhere, and depend on q. This piece of code needs to run in a quite large loop (larger than the 1:1000 given as example here), and I don't think vectorization of the entire loops is possible due to RAM issues. N is typically 16, but can be larger as well.
I use Ubuntu and MATLAB R2014a (I will probably upgrade to R2014b soon)
Thanks in advance!
N=16;
for q=1:1000
%generate some random test data
v_ustar=rand(2*N,N,N);
vstar_u=rand(2*N,N,N);
u_ustar=rand(2*N,N,N);
vstar_v=rand(2*N,N,N);
F=...
repmat(reshape(v_ustar,[2*N 1 N N]),[1 2*N 1 1]).*...
repmat(reshape(conj(vstar_u), [1 2*N N N]),[2*N 1 1 1])-...
repmat(reshape(u_ustar,[2*N 1 N N]),[1 2*N 1 1]).*...
repmat(reshape(conj(vstar_v), [1 2*N N N]),[2*N 1 1 1]);
F=reshape(F,4*N^2,[]).';
end
  4 Comments
Oleg Komarov
Oleg Komarov on 15 Oct 2014
The only small improvement I can think with this amount of code is:
F =...
bsxfun(@times, reshape(v_ustar,[2*N 1 N N]), reshape(conj(vstar_u), [1 2*N N N])) -...
bsxfun(@times, reshape(u_ustar,[2*N 1 N N]), reshape(conj(vstar_v), [1 2*N N N]));
You could get rid of the `reshape()` if you store:
v_ustar(:,1,:,:) = v_ustar_list(q1,:,:,:)
and finally get to:
F =...
bsxfun(@times, v_ustar, conj(vstar_u)) -...
bsxfun(@times, u_ustar, conj(vstar_v));
Henrik
Henrik on 15 Oct 2014
Thanks, this seems to give quite an increase in performance! If you post this as an answer I will accept it (I don't think comments can be accepted).

Sign in to comment.

Accepted Answer

Sean de Wolski
Sean de Wolski on 15 Oct 2014
Edited: Sean de Wolski on 15 Oct 2014
Another (small) improvement you can make here is to pull some of the static computations out of the loop. For example
[2*N 1 N N]
Doesn't change at all so it's being recomputed 1000x. Instead, create a variable out of it outside of the loop and then reference this variable everywhere inside it.
What do you actually end up doing with F after the loop?
I also wouldn't be surprised if splitting the F calculation into a few separate lines might help the JIT accelerator.
  2 Comments
Henrik
Henrik on 21 Oct 2014
Thanks, that did speed up the calculation a bit. Sorry I forgot to accept your answer.
Could you explain what you mean about splitting the calculation?
There's more background to what I'm trying to achieve here, if you're interested: http://www.mathworks.com/matlabcentral/answers/158214-find-zero-of-function-with-least-amount-of-iterations
Sean de Wolski
Sean de Wolski on 22 Oct 2014
When you have a really long line of code like this:
F=...
repmat(reshape(v_ustar,[2*N 1 N N]),[1 2*N 1 1]).*...
repmat(reshape(conj(vstar_u), [1 2*N N N]),[2*N 1 1 1])-...
repmat(reshape(u_ustar,[2*N 1 N N]),[1 2*N 1 1]).*...
repmat(reshape(conj(vstar_v), [1 2*N N N]),[2*N 1 1 1]);
F=reshape(F,4*N^2,[]).';
The JIT might not do as good a job optimizing it. If you break each piece, i.e. each line of repmat, into its own variable and then multiply the four variables, it might do a better job optimizing each piece.

Sign in to comment.

More Answers (0)

Categories

Find more on Loops and Conditional Statements in Help Center and File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!