How to use datestr(now)

How do I change how the date is written when I use datestr?

It displays 29-Sep-2014 but I want it to say 29.september year 2014

?

Answer 1

[José-Luis]

vec = datevec(now);
month_list = {'January' 'February' 'March' 'April' 'May' 'June' ...
    'July' 'August' 'September' 'October' 'November' 'December'};

your_string = sprintf('%i.%s year %i',vec(3),month_list{vec(2)}, vec(1))

Please accept the answer that best solves your problem.

Answer 2

[Azzi Abdelmalek]

strrep(datestr(now,'dd.mmmm _ yyyy'),'_','year')

[José-Luis]

month_list = {'January' 'February' 'March' 'April' 'May' 'June' ...
    'July' 'August' 'September' 'October' 'November' 'December'};
tic 
vec = datevec(now);
your_string = sprintf('%i.%s year %i',vec(3),month_list{vec(2)}, vec(1));
toc 
tic
strrep(datestr(now,'dd.mmmm _ yyyy'),'_','year');
toc

Elapsed time is 0.000384 seconds.

Elapsed time is 0.091557 seconds.

I just felt the need to pointlessly discuss this.

[Azzi Abdelmalek]

You can't make a comparison like that. With your code I found

Elapsed time is 0.013061 seconds.
Elapsed time is 0.003681 seconds.

[Azzi Abdelmalek]

Using a for loop

month_list = {'January' 'February' 'March' 'April' 'May' 'June' ...
  'July' 'August' 'September' 'October' 'November' 'December'};
tic 
for k=1:10000
vec = datevec(now);
your_string = sprintf('%i.%s year %i',vec(3),month_list{vec(2)}, vec(1));
end
toc 
tic
for k=1:10000
strrep(datestr(now,'dd.mmmm _ yyyy'),'_','year');
end
toc

Elapsed time is 0.788404 seconds.

Elapsed time is 2.663671 seconds.

[José-Luis]

I don't see why the comparison should be invalid. It is faster even if I include the cell array generation in the computation time:

tic 
month_list = {'January' 'February' 'March' 'April' 'May' 'June' ...
    'July' 'August' 'September' 'October' 'November' 'December'};
vec = datevec(now);
your_string = sprintf('%i.%s year %i',vec(3),month_list{vec(2)}, vec(1));
toc 
tic
strrep(datestr(now,'dd.mmmm _ yyyy'),'_','year');
toc

Elapsed time is 0.000576 seconds.

Elapsed time is 0.001291 seconds.

Answer 3

[Thorsten]

[datestr(now, 'dd.mmmm') ' year ' datestr(now, 'yyyy')]