How to convert 4 by 8 matrix bytevalues to correspond to a 4 by 1 milliseconds

Milliseconds = convert_bytes_to_ms(uint64(millis));millis = [50 20 45 55 46 65 48 70;40 42 56 67 60 45 39 53; 50 54 51 65 64 70 48 49;45 39 50 56 58 69 47 62]

Answer 1

[Harimurali]

Hi Uzochukwu,

I understand that you want to convert a 4x8 matrix of byte values to correspond to a 4x1 millisecond matrix.

Byte values should be considered as time intervals and scaled accordingly to perform this conversion.

Follow these steps to convert the given 4x8 matrix of byte values to a 4x1 matrix with millisecond values:

• Define a conversion factor that represents the time interval per byte value. Let's assume each byte value represents 1 millisecond.
• Create a 4x1 matrix to store the converted time values.
• Iterate through each row of the 4x8 matrix and sum up the byte values in each row.
• Multiply the sum of each row by the conversion factor to obtain the corresponding time value.
• Store the calculated time value in the corresponding row of the 4x1 matrix.

Please refer to the following sample MATLAB code that implements the above steps:

millis = [50 20 45 55 46 65 48 70;40 42 56 67 60 45 39 53; 50 54 51 65 64 70 48 49;45 39 50 56 58 69 47 62]; 
conversionFactor = 1;  % Assuming each byte value represents 1 millisecond 

Milliseconds = zeros(4, 1); 
for row = 1:4 
    sumBytes = sum(millis(row, :)); 
    Milliseconds(row) = sumBytes * conversionFactor; 
end 

I hope this helps.