rmfield / clear structur entry ?

hey Guys, I have got a 1xn structure. Now i just want to write a code which can delete on column of a structure. For example:

A is structure with A.x / A.y /A.z This is a 1x5 structure. Now I want to make this a 1x4 structure by deleting the 3rd Column. So A(3) is gone and A(4) is now the new A(3) / A(5) is the new A(4)

Answer 1

[Azzi Abdelmalek]

A=struct('x',num2cell(rand(1,5)),'y',num2cell(rand(1,5)),'z',num2cell(rand(1,5)))
A(3)=[]

[Max Müller]

tried this already...somehow it doesnt work

for u = 1:length(A)
             Check = A(u).UsedAmp + A(u).OptimalAmp + A(u).ClosestAmp;
             if Check == 0;
                 A(u) = [ ];
             end
         end

[Pierre Benoit]

It may not work because each time you set A(u) to 0, the length of A will reduce, so you will exceed matrix dimensions at some point.

Try this :

Check = [A.UsedAmp] + [A.OptimalAmp] + [A.ClosestAmp];
A(Check == 0) = [];

If it's still doesn't work, it may be that you didn't define your condition correctly.

[Max Müller]

Your are right! If Check == 0 deletes one part of the structure, it exceedes the matrix dimension.

[Azzi Abdelmalek]

A=struct('UsedAmp',num2cell([1 2 3 4 5]),'OptimalAmp',num2cell([-1 2 3 4 -3]),'ClosestAmp',num2cell([0 2 3 4 -2]))
idx=[];
for u = 1:numel(A)
  Check = A(u).UsedAmp + A(u).OptimalAmp + A(u).ClosestAmp;
  if Check == 0;
      idx(end+1)=u
  end
end
A(idx)=[]

[Azzi Abdelmalek]

Or

A=struct('UsedAmp',num2cell([1 2 3 4 5]),'OptimalAmp',num2cell([-1 2 3 4 -3]),'ClosestAmp',num2cell([0 2 3 4 -2]))
A(squeeze(sum(cell2mat(struct2cell(A))))==0)=[]