For loop not generating result
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I have the equation below to program
k should assume 1 if
≥
and assume 0 if
≤
.
All other parameters are constants.
R = 2; C = 2.5; eta = 2.5; Pac = 5; Tp = 76; t_delta = 1;
t = 0:5/12:24;
alpha = 1-t_delta/(60*R*C);
beta = eta*R*(9/5)+32;
T0 = 86 - 14*cos(0.0035*t);
Ta(1) = Tp;
k(1) = 0;
for j = 1:length(t)
Ta(j+1) = alpha*Ta(j)+(1-alpha).*(T0(j)-k(j)*beta*Pac);
if (Ta(1:j) <= Tp-0.5)
k(j) = repelem(0,length(j));
Ta(j+1) = alpha*Ta(j)+(1-alpha).*(T0(j)-k(j)*beta*Pac);
for m = 1:j
if (Ta(1:m) >= Tp+0.5)
k(m) = repelem(1,length(m));
Ta(m+1) = alpha*Ta(m)+(1-alpha).*(T0(m)-k(m)*beta*Pac);
end
end
end
end
plot(t,Ta) suppose to give a pulse-like shape, similar to the shape in orange in the attached file. But I'm not getting anything close.
I don't know what is wrong. Please assist. I'm very new to matlab.
7 Comments
Cris LaPierre
on 6 Oct 2021
Depending how new to MATLAB you are, you may find going through MATLAB Onramp will get you up to speed faster than going it alone.
One question about your code. What do you want the result of this line of code to be?
t = 0:5/12:24;
shaddai
on 6 Oct 2021
Cris LaPierre
on 6 Oct 2021
Edited: Cris LaPierre
on 6 Oct 2021
When I try to run your code, I get an error in the indexing a k. Basically, when you code loops the second time, k still only has 1 value in it, but your calcualtion tries to index the 2nd value, which doesn't exist.
a=0;
% works
a(1)
% doesn't work
a(2)
shaddai
on 6 Oct 2021
Cris LaPierre
on 6 Oct 2021
Edited: Cris LaPierre
on 6 Oct 2021
Your code will create k as a vector. The issue is your assignment is one step behind where it needs to be.
There is also a question of what the value of k should be if
?
?
Cris LaPierre
on 7 Oct 2021
Nice. I suggest moving you last post to an Answer. You can accept your own answer, and doing so will let others know this question has a solution.
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