how to evaluate equation at different values?

I'd like to find and save x at different values of mu.

Itried to write mu=linspace (2.4,4,1000) but I did not know how to complete the code.

Can you please help me.

mu=linspace(2.4,4,1000);
x(1)=.5;
    for i=1:10
      x(i+1)=mu*x(i)*(1-x(i));
    end

Answer 1

[KSSV]

mu=linspace(2.4,4,1000);
x = zeros(size(mu)) ; 

x(1)=.5;
for i=1:10
    x(i+1)=mu(i)*x(i)*(1-x(i));
end

plot(mu,x)

[Omar B.]

I should get x values per mu.

how to find x_data using the folowing equation

%---------------------------
for i=1:n
x(i+1)=mu*x(i)*(1-x(i))
end

[KSSV]

No equation for x_data is given.

[Omar B.]

it is the following

x(i+1)=mu(i)*x(i)*(1-x(i));

I should get x values per one value of mu

[Walter Roberson]

mu_min=2.4; mu_max=4; %range of mu values
 n_mu=500; %number of mu pixels
 n_x=400; %number of x pixels
 mu_edges=linspace(mu_min,mu_max,n_mu+1); %edges of mu pixels
 mu=(mu_edges(1:n_mu)+mu_edges(2:n_mu+1))/2; %values of mu on which to perform computation
 x_edges=linspace(0,1,n_x+1); %edges of x pixels
 n_trans=200000; %transient iterations
n_data=100000;  %number of x values per mu value
 x_data=zeros(n_data,n_mu); %x-data used to construct figure
 
 num_mu = length(mu);
 
 x(1,1:num_mu)=0.5; %initial condition

%---------------------------
for i=1:30  %should be n_trans
  x(i+1, :) = mu .* x(i, :) .* (1-x(i,:));
end

plot(x)

[Omar B.]

Thank you so much.