# I have created a function that relies on a guess, and now I need to create a for loop for that function that plugs in the answer it gives back in to the "OLD" original guess.

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Colton McGarraugh on 15 Sep 2021
Commented: Mathieu NOE on 21 Sep 2021
I have to turn my function into a for loop that plugs "f" back in where "OLD" is, as "OLD" is the original guess for f. I have created this for loop using my professsors advice, but I keep getting errors. Is there a trick for the for loop that I am missing or am I just not doing it correctly?
%% Inputs
E=0.00015; % (m) Surface Roughness
D=0.315; % (m) Hydraulic Diameter
R=125000; % (unitless) Reynolds Number
OLD=0.1; % (unitless) Friction Factor ; Initial Guess for RHS of Equation 1
%% Function Definitions
[f]=colebrook(E,D,R,OLD);
%% Code
function [f] = colebrook(E,D,R,OLD)
f=1/(-2*log10(((E/(3.7*D))+2.51/(R*sqrt(OLD)))))^2;
for i=1:50
f(i)=OLD(i);
end
end

Mathieu NOE on 16 Sep 2021
hello
yes , your "recursion" is not really working
this works
Once you're satisfied with the code , you can reùove / comment the two lines where you see : % debug only
code :
%% Inputs
E=0.00015; % (m) Surface Roughness
D=0.315; % (m) Hydraulic Diameter
R=125000; % (unitless) Reynolds Number
f_init=0.1; % (unitless) Friction Factor ; Initial Guess for RHS of Equation 1
%% Function Definitions
[f]=colebrook(E,D,R,f_init);
%% Code
function [f] = colebrook(E,D,R,f_init)
f = f_init;
for ci=1:10
f_new = 1/(-2*log10(((E/(3.7*D))+2.51/(R*sqrt(f)))))^2;
f = f_new;
f_save(ci) = f; % debug only
end
plot(f_save);% debug only
end
Mathieu NOE on 21 Sep 2021
hello
if my submission has helped you, do you mind accepting it ?
tx

R2021a

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