# 51 uniformly-distributed points

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Jamie Williamson on 15 Sep 2021
Edited: Dave B on 15 Sep 2021
I have a question asking for 51 uniformly distributed points. How might this be done?
Replaces the continuous domain of xM from 0 to 5 (i.e. 0 ≤ xM ≤ 5) with a set of 51 uniformly-distributed points.

Dave B on 15 Sep 2021
Edited: Dave B on 15 Sep 2021
You can create uniformly (linearly) distributed values with the linspace function:
x = linspace(0, 5, 51)
x = 1×51
0 0.1000 0.2000 0.3000 0.4000 0.5000 0.6000 0.7000 0.8000 0.9000 1.0000 1.1000 1.2000 1.3000 1.4000 1.5000 1.6000 1.7000 1.8000 1.9000 2.0000 2.1000 2.2000 2.3000 2.4000 2.5000 2.6000 2.7000 2.8000 2.9000
Alternatively, you might have noticed that the set of points you're looking for are 0.1 increments, and could have used the colon operator to accomplish the same:
x = 0:.1:5
x = 1×51
0 0.1000 0.2000 0.3000 0.4000 0.5000 0.6000 0.7000 0.8000 0.9000 1.0000 1.1000 1.2000 1.3000 1.4000 1.5000 1.6000 1.7000 1.8000 1.9000 2.0000 2.1000 2.2000 2.3000 2.4000 2.5000 2.6000 2.7000 2.8000 2.9000

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