Changing hair color in a photo using matlab

rgbColorImage = imread('peppers.png');
% Extract the individual red, green, and blue color channels.
          redChannel = rgbColorImage{ii}(:, :, 1);
          greenChannel = rgbColorImage{ii}(:, :, 2);
          blueChannel = rgbColorImage{ii}(:, :, 3);
          % Specify the color we want to make this area.
          desiredColor = [146, 40, 146]; % Purple
          % Make the red channel that color
          redChannel(maskedImage) = desiredColor(1);
          greenChannel(maskedImage) = desiredColor(2);
          blueChannel(maskedImage) = desiredColor(3);
          % Recombine separate color channels into a single, true color RGB image.
          rgbColorImage{ii} = cat(3, redChannel, greenChannel, blueChannel);

Undefined function or variable 'ii'.

Error in color_change_red_into_blue (line 92)

redChannel = rgbColorImage{ii}(:, :, 1);

I get this error. What do you recommend ?

[DGM]

See also:

https://www.mathworks.com/matlabcentral/answers/350829-how-can-i-change-the-color-of-the-hair-such-that-it-has-the-same-texture-as-the-original-hair

Answer 1

[Image Analyst]

rgbImage is not a cell array so you don't use braces. Get rid of the {ii}. It should be done like

% Extract the individual red, green, and blue color channels.
[redChannel , greenChannel,  blueChannel] = imsplit(rgbColorImage);

maskedImage has not been defined at all, so that will cause an error when your program gets to that. You need to define maskedImage as a binary image in order to use it as a logical image like you're trying.

[yasar ismet Yilmaz]

          rgbColorImage = imread('peppers.png');
          redChannel = rgbColorImage(:, :, 1);
          greenChannel = rgbColorImage(:, :, 2);
          blueChannel = rgbColorImage(:, :, 3);
          % istediğimiz rengi belirtin.
          desiredColor = [146, 40, 146]; % Purple
          % Make the red channel that color
          redChannel(maskedImage) = desiredColor(1);
          greenChannel(maskedImage) = desiredColor(2);
          blueChannel(maskedImage) = desiredColor(3);
          % Ayrı renk kanallarını tek bir gerçek renkli RGB görüntüsünde yeniden birleştirin.
          rgbColorImage = cat(3, redChannel, greenChannel, blueChannel);
          [redChannel , greenChannel,  blueChannel] = imsplit(rgbColorImage);

Undefined function or variable 'maskedImage'.

Error in color_change_red_into_blue (line 98)

redChannel(maskedImage) = desiredColor(1);

I got error again. Help me. @Image Analyst

[Image Analyst]

Again, "maskedImage has not been defined at all, so that will cause an error when your program gets to that. You need to define maskedImage as a binary image in order to use it as a logical image like you're trying."

try using the ColorThresholder app on the Apps tab of the tool ribbon and Export the function to get a mask and the masked image. You will use only the mask, not maskedImage.

[yasar ismet Yilmaz]

I created the image where I changed the hair color and saved it to Workspace. How do I print my saved photo to the screen? (sorry i asked a lot of questions)

[Image Analyst]

OK, good. Glad you got it working. To display (not print) the image to the screen you can use imshow():

imshow(rgbImage);

assuming the variable you saved to the workspace is called rgbImage.