plot the equation graph

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shiv gaur
shiv gaur on 30 Aug 2021
Commented: shiv gaur on 25 Sep 2021
how to plot graph V vs x
equation is
V*sqrt(1-x)=m*pi+atan((x)/(1-x))+atan((a+x)/(1-x))
taking V=1:10
m=0
a=1;
then plot V vs x
  3 Comments
shiv gaur
shiv gaur on 30 Aug 2021
sorry for inconviniennce but graph is not showing exact value on page 63 fig 3.14 for a=10 the answer is not showing as shown in fig equation 3,44 sorry again for again

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Answers (1)

Wan Ji
Wan Ji on 30 Aug 2021
Hi,
It is not neccessary to solve this equation
x = 0:0.00001:1;
f = @(x,m,a)(m*pi+atan((x)/(1-x))+atan((a+x)/(1-x)))./sqrt(1-x);
m = [0,1,2];
a = [0,10,1e15];
V1 = f(x,m(1),a(1));
V2 = f(x,m(1),a(2));
V3 = f(x,m(1),a(3));
plot(V1,x)
hold on
plot(V2,x)
plot(V3,x)
V1 = f(x,m(2),a(1));
V2 = f(x,m(2),a(2));
V3 = f(x,m(2),a(3));
plot(V1,x)
hold on
plot(V2,x)
plot(V3,x)
V1 = f(x,m(3),a(1));
V2 = f(x,m(3),a(2));
V3 = f(x,m(3),a(3));
plot(V1,x)
hold on
plot(V2,x)
h = plot(V3,x);
axis([0, 15, 0, 1.1])
grid on
  8 Comments
Wan Ji
Wan Ji on 30 Aug 2021
you can change x0,x1 and x2 to get more roots if there are
shiv gaur
shiv gaur on 25 Sep 2021
Mj=[cos (kj hj) i*sin(kj hj) /kj ; i*kj*sin(kj hj) cos (kj hj) ];
kj=sqrt(nj2*k02-x2);
Take n1=1.521;n2=2.66;k0=1;h1=1.5e-6;h2=1e-6
We take M=M1*M2;
Where M=( m11 m12;m21 m22) as usual in
Matrix;
How to multiply this matrix for M find the multiplication of matrix and find the value of
x;
and solve the eq
ns=1.512;
nc=1.2-i7;
gs=x2-ns2k02;
gc= x2-ns2k02;
f(x)=igsm11+gcm22)-m21+gsgcm12;
and solve the eq and value of x

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