Subgraph from selected edges

Hi, is it possible to extract a subgraph by selecting the edges, instead of nodes? If Yes, how?
From the Matlab docs, I can see it is possible by selecting the nodes, but not the edges:
H = subgraph(G,nodeIDs)
H = subgraph(G,idx)

 Accepted Answer

Wan Ji
Wan Ji on 20 Aug 2021
Edited: Wan Ji on 21 Aug 2021
Note that all the endnodes of some given edges may be repeated, as commented by @Sim. Unique is a good way to solve such problem, to the example provided by Sim, now the code is modified as
clc; close all; clear all;
s = [1 1 1 1 2 2 2 2 2 2 2 2 2 2 15 15 15 15 15];
t = [2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20];
x = [1 2 0 0 0 1 7 8 9 10 1 2 4 3 5 6 7 8 9 10];
y = [0 1 0 1 2 2 0 1 2 3 4 5 3 5 6 3 4 6 7 8];
G = graph(s,t);
G.Nodes.X = x(:);
G.Nodes.Y = y(:);
EdgeNumber = [1 2 15] ; % the no. of egde
EndNodes = G.Edges.EndNodes(EdgeNumber,:)
H = subgraph(G, unique(EndNodes));
figure
hold on
plot(G,'XData',x,'YData',y,'EdgeColor','blue','LineWidth',1)
h = plot(H,'XData',H.Nodes.X,'YData',H.Nodes.Y,'EdgeColor','red','LineWidth',2);
h.NodeLabel = {};
It is found that this method includes one edge more, i.e. the edge (2,15) in G. This is OK, because what the method provide is the subgraph connected with these 5 nodes.
IF YOU WANT TO get subgraph really by edges. Then
s = [1 1 1 1 2 2 2 2 2 2 2 2 2 2 15 15 15 15 15];
t = [2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20];
x = [1 2 0 0 0 1 7 8 9 10 1 2 4 3 5 6 7 8 9 10];
y = [0 1 0 1 2 2 0 1 2 3 4 5 3 5 6 3 4 6 7 8];
G = graph(s,t);
G.Nodes.X = x(:);
G.Nodes.Y = y(:);
EdgeNumber = [1 2 15] ; % the no. of egde
EndNodes = G.Edges.EndNodes(EdgeNumber,:);
[q, ~, ic]= unique(EndNodes);
p = 1:1:numel(q);
st = p(reshape(ic,size(EndNodes)));
sub_Graph_by_Egde = graph(st(:,1), st(:,2));
sub_Graph_by_Egde.Nodes.X = G.Nodes.X(q,:);
sub_Graph_by_Egde.Nodes.Y = G.Nodes.Y(q,:);
figure
hold on
plot(G,'XData',x,'YData',y,'EdgeColor','blue','LineWidth',1)
h = plot(sub_Graph_by_Egde,'XData',sub_Graph_by_Egde.Nodes.X,...
'YData',sub_Graph_by_Egde.Nodes.Y,'EdgeColor','red','LineWidth',2);
I think I have solved your problem

3 Comments

Sim
Sim on 20 Aug 2021
Edited: Sim on 20 Aug 2021
Cool, many thanks @Wan Ji !
However, this works only with 1 edge:
clc; close all; clear all;
s = [1 1 1 1 2 2 2 2 2 2 2 2 2 2 15 15 15 15 15];
t = [2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20];
x = [1 2 0 0 0 1 7 8 9 10 1 2 4 3 5 6 7 8 9 10];
y = [0 1 0 1 2 2 0 1 2 3 4 5 3 5 6 3 4 6 7 8];
G = graph(s,t);
G.Nodes.X = x(:); G.Nodes.Y = y(:);
EdgeNumber = [10] ; % the no. of egde
EndNodes = G.Edges.EndNodes(EdgeNumber,:)
H = subgraph(G, EndNodes);
figure
hold on
plot(G,'XData',x,'YData',y,'EdgeColor','blue','LineWidth',1)
h = plot(H,'XData',H.Nodes.X,'YData',H.Nodes.Y,'EdgeColor','red','LineWidth',2);
h.NodeLabel = {};
Which gives me this result:
EndNodes =
2 11
How to make it work for many EdgeNumber ?
Fantastic @Wan Ji, you totally nailed it! Very grateful!
Issue solved! :-)
hello sir
how to split subgraphs(by selected edges) from given complete graph in matlab sir?

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More Answers (1)

Wan Ji
Wan Ji on 20 Aug 2021
hi, friend, you can make EdgeNumber an array that contains all the edge numbers that you are interested in. and make the line H = subgraph(G, EndNodes); changed as H = subgraph(G, EndNodes(:));

3 Comments

Sim
Sim on 20 Aug 2021
Edited: Sim on 21 Aug 2021
Hi, thanks for the nice reply... I used
H = subgraph(G, unique(EndNodes));
instead of your suggestion:
H = subgraph(G, EndNodes(:));
since, with your hint, it gave me the following error:
Error using graph/subgraph (line 40)
Nodes must be a vector of unique node indices, a vector of unique node names, or a logical vector of length equal to the number of
nodes.
Now it works, but there is still an important issue to fix.
In this example:
clc; close all; clear all;
s = [1 1 1 1 2 2 2 2 2 2 2 2 2 2 15 15 15 15 15];
t = [2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20];
x = [1 2 0 0 0 1 7 8 9 10 1 2 4 3 5 6 7 8 9 10];
y = [0 1 0 1 2 2 0 1 2 3 4 5 3 5 6 3 4 6 7 8];
G = graph(s,t);
G.Nodes.X = x(:); G.Nodes.Y = y(:);
EdgeNumber = [1 2 15] ; % the no. of egde
EndNodes = G.Edges.EndNodes(EdgeNumber,:)
H = subgraph(G, unique(EndNodes));
figure
hold on
plot(G,'XData',x,'YData',y,'EdgeColor','blue','LineWidth',1)
h = plot(H,'XData',H.Nodes.X,'YData',H.Nodes.Y,'EdgeColor','red','LineWidth',2);
h.NodeLabel = {};
the result is:
EndNodes =
1 2
1 3
15 16
However, in the subgraph H I have an additional edge, i.e 4 edges, instead of 3 edges:
>> H.Edges
ans =
1 2
1 3
2 4
4 5
which can be seen in the following picture too (here, the nodes labels refer to G and not to H):
This is due to the fact that I had to take the unique nodes in G, as required by the subgraph function:
H = subgraph(G,nodeIDs)
i.e.
>> unique(EndNodes)
ans =
1
2
3
15
16
In summary, this method includes one edge more, i.e. the edge (2,15) in G:
EndNodes =
1 2
1 3
2 15
15 16
If we can solve this issue it is done!
yes, you have done a good job, 👍👍👍
many thanks @Wan Ji! :)

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Asked:

Sim
on 20 Aug 2021

Commented:

on 25 Jun 2023

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