Extend a vector by extending its elements

I have a vector of dimension d: (1,2,...,d) (it's (x_1,x_2,...,x_n) but I removed the 'x_' for simplicity). Now I would like to extend it (in a fast manner) to obtain a d*d vector of the form:
(1,1,...,1,2,...,2,...,d,d,...,d)
where each element repeat d times.
I looked at this page: http://www.mathworks.fr/fr/help/wavelet/ref/wextend.html but it seems to me that the function does not handle this kind of extension.
Thank you for your help.

 Accepted Answer

Udit Gupta
Udit Gupta on 29 May 2014
Edited: Udit Gupta on 29 May 2014
If your vector is X.
reshape(repmat(X,d,1),1,[])
should do the trick.
Example -
>> X = [1 2 3 4];
>> d=4;
>> reshape(repmat(X,d,1),1,[])
ans =
1 1 1 1 2 2 2 2 3 3 3 3 4 4 4 4

3 Comments

Thanks, Udit. If X is a column vector, then is there a way to avoid transposing and then re-transposing again the final vector?
reshape(repmat(X,d,1),[],1) will give you a column vector. But in this case you will have to transpose the original vector. SO you will apply -
reshape(repmat(X',d,1),[],1)
Thanks, Udit!

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More Answers (3)

If X is a column vector:
% initial data
d=10;
% engine
X=(1:d)';
ind=ones(d^2,1);
ind(d+1:d:d^2)=1-d;
% result
output_vector=X(cumsum(ind))
If X is a row vector:
% initial data
d=10;
% engine
X=1:d;
ind=ones(d^2,1);
ind(d+1:d:d^2)=1-d;
% result
output_vector=X(cumsum(ind))
without the need to reshape or repmat!

1 Comment

Thanks, George. I will compare with Udit's solution and get back to you.

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Jos (10584)
Jos (10584) on 29 May 2014
Edited: Jos (10584) on 29 May 2014
A slower but nice alternative to repmat:
X = [10 20 30 40]
d = 4
Y = kron(X, ones(1,d))
Jos (10584)
Jos (10584) on 29 May 2014
Edited: Jos (10584) on 29 May 2014
A fast and also nice alternative:
X = [10 ; 20 ; 30 ; 40]
d = 3
Y = X(ceil((1:d*numel(X))/d))

1 Comment

Thanks, Jos. I will compare with Udit's solution and get back to you.

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