Can I use a for loop in the condition statement of an if branch??
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I am trying to pick selected values of out one array and assign them to a new array. The condition for this 'picking' needs to have a for loop. I mean, the condition must be repeated for a given number of times. So, can I use a 'for' loop in the condition statement of the 'if'?? I have tried the other way round, where the 'if' comes inside 'for' and I have obtained erroneous results. If I am not allowed to do the above, kindly direct me as to how I could solve such an issue.
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Answers (2)
Simon
on 7 Jan 2014
Can you give an example? As far as I understand you have some values in your array that must match some condition. You may write this without loops like
if (samplearray([1 4 6]) == [1 2 3])
...
end
3 Comments
Simon
on 7 Jan 2014
Hi!
Just use a logical variable like
ConditionMet = true
for n = 1:NumberOfConditions
% check current condition
if ~(...)
ConditionMet = false
end
end
% now your if
if ConditionMet
...
else
...
end
David Sanchez
on 7 Jan 2014
No, you can not use a for-loop as the condition of an if statement as in the following WRONG code:
if (for k=1:3 k=k end)
disp('correct expression');
end
In case your if-statement needs more than one condition to be fulfilled, you have to use && to add them up.
if (1==1 && 2==2 && 3==3)
disp('correct expression');
end
2 Comments
David Sanchez
on 7 Jan 2014
Sorry for the misunderstanding, can you provide some pseudo-code of what you need? I'm pretty sure you can do what you want but some code/pseudo-code would be of great help in order to give a more precise answer.
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