how do you write a conditional struct?

 Accepted Answer

At the beginning start with
data = [];
Then, in each of the error cases, after you disp() the string, add
return
before the "end" of the "if"
if condition
disp('message')
return
end

More Answers (1)

Maybe you are asking about if/elseif/else

4 Comments

i tried using if, but it doesnt work :( can you give a simple example
Matt J
Matt J on 18 Nov 2013
Edited: Matt J on 18 Nov 2013
@vishant
Why don't you give an example of what doesn't work and describe what you want to happen instead.
function data=test3(n)
if isnumeric(n)==0;
n=([1 2 3 4]); display('input has two many terms or is not a vector');
end
if isvector(n)==0;
n=([1 2 3 4]); display('input has two many terms or is not a vectorl');
end
x=linspace(-5,5,1000);
y=polyval(n,x);
plot(x,y);
q=roots(n);
data=plot(q(imag(q)==0), zeros(sum(imag(q)==0)),'r+');
data= struct('x',x,'p',n,'rp',q,'rpp',q(imag(q)==0),'px',(x));
end
this is the code, you can see the struct. there are 2 if functions at the start, i need the struct to give ans[] when the condition of any of the ifs applies.
[i need the struct to give ans[] when the condition of any of the ifs applies.] I can't understand what you mean

Sign in to comment.

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!