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Is there is a way I can select the minimum value from a matrix, and replace all numbers surrounding this minimum value (3 cells) by a specific number

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I want to select this minimum value cell, and anything within a radius of ‘less than or equal to’ three cells to be replaced with a specific number such as 99 (including the selected minimum cell).
I have uploaded a pdf of what i am trying to accomplish. Sorry for any inconvenience and thank you.

Accepted Answer

dpb
dpb on 9 Nov 2013
Edited: Andrei Bobrov on 10 Nov 2013
[~,imin]=min(x(:)); % location of min (linear
[im,jm]=ind2sub(size(x),imin); % convert to subscripts
x(im-1:im+1,jm-1:jm+1)=99; % set a square around that location
  6 Comments
Ruby
Ruby on 11 Nov 2013
Regarding the 'setting a square perimeter' around the min value, if the min value is in either column 1 or row 1, it shows an error message. This is because there are no numbers around the edge of the matrix so it cant set them as 99. Is there any way around this error?
dpb
dpb on 11 Nov 2013
You'll have to write logic to handle the condition; there's no automagic way that I can think of. Wrapping the bounds expressions inside min and max is one way can do that so that, for instance, the LHS x-bound becomes
max(im-1,1)
Similar logic w/ proper limits for the other directions should be obvious extension. The end keyword is invaluable in such instances for upper bound values, btw...

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