[ASK] Euclidean Distance
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how to find the distance between a webcam with an object ..?
Accepted Answer
More Answers (3)
Christopher Jones
on 29 Oct 2013
0 votes
That's a rather general and open ended question. Care to elaborate?
11 Comments
Malta
on 29 Oct 2013
Image Analyst
on 29 Oct 2013
Then I think a tape measure or a scale/ruler would be the most appropriate tool to set up the distance between your camera and your subject (the id card).
Malta
on 29 Oct 2013
Walter Roberson
on 7 Nov 2013
You appear to have a known distance of "10cm". Is that the distance between the webcam and the ID card? Or is that the known physical distance between two items on the ID card? Are you trying to find the distance between the webcam and the ID card, or are you trying to find the "real-world" size of the ID card, or do you know the real size of the ID card and are trying to find the distance between two items on it, or something else?
Malta
on 8 Nov 2013
Walter Roberson
on 8 Nov 2013
What information do you have that is known ahead of time, other than that the id card is between 10cm and 20cm away from the webcam? For example, is the entire id card certain to be visible within the image, and is the ID card a known size?
Malta
on 8 Nov 2013
Walter Roberson
on 9 Nov 2013
Wait -- do you have a fixed size but moving object, and you want to capture the image only if the object is between 10 cm and 30 cm away?
Malta
on 9 Nov 2013
Walter Roberson
on 9 Nov 2013
Is the ID card a fixed size?
Image Analyst
on 8 Nov 2013
0 votes
Malta, like I said, just use a ruler to position your webcam about 10 cm from your card. Make sure that that you can still get an image that is in focus, because that is pretty close and it might be blurry. So once you have that you need to spatially calibrate your scene before you can make laterla measurements from it. For that, please see my calibration demo attached below (simply copy and paste and run).
3 Comments
Malta
on 8 Nov 2013
Sean de Wolski
on 8 Nov 2013
doc bwdist
bwdist has a euclidean option. I don't see how it'll help you (as IA has pointed out).
Image Analyst
on 8 Nov 2013
Malta: In the code you'll see the line:
lineLength = round(sqrt((xi(1)-xi(2))^2 + (yi(1)-yi(2))^2))
so I did use Euclidean distance.
At this point I don't know how to help you because after many questions we still don't know what you want to take the Euclidean distance of: the distance from your camera to the card, or laterally between two points on the card.
Moreover, I don't know what level of coding I can give you. If I give you something simple, like the line above, it's basically useless because you'll need other code to get the x and y coordinates. But if I give you code for that, like in the attached short and simple example, you say it's too complicated for your to understand. I don't know how to give you anything in between that would be usable by you. For example I could hard code x and y like this:
x = [2 4];
y = [5 9];
lineLength = sqrt((x(1)-x(2))^2 + (y(1)-y(2))^2))
but that's not really any help to you because those x and y are not what you'll be using, so then you're basically going to have to do something like I gave in the example, which you said was too difficult to understand. I'm sorry that I'm not able to find the right level of complexity that you will be able to understand, and at the same time be useful to you.
Walter Roberson
on 8 Nov 2013
0 votes
With that set-up it is not possible to find "distance between webcam with an object", "using euclidean distance". If an object in an image is 100 pixels long, you cannot tell if the object was 100 units long photographed at 10 cm, or 200 units long photographed at 20 cm.
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