How to fill in this matrix?

I have a 3x1536 matrix named time

On the 2nd row I'm trying to fill it in with hours of the day but I need four of each hour so for example:

1 1 1 1 2 2 2 2 3 3 3 3...24 24 24 24 1 1 1 1 2 2 2 2 and so on

.

I have no idea how to go about indexing the matrix in a way that I don't have to write then modify 96 loops/indexing lines of code because I have to fill it out in the only way I can think of right now which is:

for a=1:96:1536

      time(2,a)=0;

end

.

for b=2:96:1536

      time(2,b)=0;

end

...

for e=5:96:1536

      time(2,e)=1;

end

Answer 1

[Azzi Abdelmalek]

Edit

n=1536/4
c2=repmat(1:n,4,1);
time(2,:)=circshift(mod(c2(:)',24)+1,[0 4])

%or

n=1536/(24*4)
a=repmat(1:24,4,1)
time(2,:)=repmat(a(:)',1,n)

[Azzi Abdelmalek]

Look at Edit

Answer 2

[Walter Roberson]

time(2,:) = reshape(kron(1:24, ones(16,4)), 1, []);

[Andrei Bobrov]

reshape(kron(1:24, ones(16,4))',1,[])

or

reshape(kron((1:24)', ones(4,16)),1,[])

Answer 3

[Andrei Bobrov]

reshape(repmat(1:24,[4,1,16]),1,[])

Answer 4

[Jos (10584)]

There are many roads to Rome. Here is another generic and fast solution:

% example data  
time = zeros(3,26) % in your case: 3-by-1536
Nval = 6 % in your case : 24
Nrep = 3 % in your case : 4

% engine
time(2,:) = mod(floor((0:(size(time,2)-1))/Nrep), Nval) + 1