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how we can define piecewise function in matlab?
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in maple we can use comamnd:(
f:= piecewise(0 <= t and t <= T1, f1, T1 < t and t < T2, 0, T2 <=t and t <= T3, f1, T3 < t and t < T4, 0)
but in matlab i can not define this function.
please give me som information ...
thanks
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Accepted Answer
Sally Al Khamees
on 23 Dec 2016
Edited: Sally Al Khamees
on 21 Feb 2017
If you have R2016b and the Symbolic Math Toolbox installed, you can just use the piecewise function:
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/176218/image.png)
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More Answers (3)
Walter Roberson
on 12 Oct 2013
You cannot define that as a function in MATLAB. MATLAB functions need to have a defined value for the case where none of the conditions hold. If you were absolutely sure that one of the conditions will hold you would rewrite the Maple function without the final condition, as
piecewise(0 <= t and t <= T1, f1, T1 < t and t < T2, 0, T2 <=t and t <= T3, f1, 0)
This would be
function y = f(t, T1, T2, T3, f1)
y = zeros(size(t));
idx1 = 0 <= t & t <= T1;
y(idx1) = f1;
idx2 = T1 < t & t < T2;
y(idx2) = 0;
idx3 = T2 <= t & t <= T3;
y(idx3) = f1;
y(~(idx1 | idx2 | idx3)) = 0;
end
4 Comments
Walter Roberson
on 21 Feb 2017
Note: my later experiments showed that using sym('t->...') cannot possibly create a symbolic function.
sixwwwwww
on 12 Oct 2013
Dear ebi, You need something like this if I understood correctly:
syms f f1
t = input('Enter value of t: ');
% Assuming values of T1, T2 and T3 as follows
T1 = 10;
T2 = 20;
T3 = 30;
if ((t >= 0 && t <= T1) || (t >= T2 && t <= T3))
f = f1; % here you can define f1 as you wish
else
f = 0;
end
Is it ok?
3 Comments
sixwwwwww
on 12 Oct 2013
Do you input 't' as a time vector? and get f(t) for which you can calculate fft? Is it right?
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