extract data from a 1D vector with a pattern

1 view (last 30 days)
I have a 1D vector A=[1:1000]. I would like to start from the first elemnt of A and automatcially extract every first 16 elemnts but exclude the next 8 elements, and continue to end. In the end I have two vectors A1 (has every chunks of 16 elemnets) and A2 (every other chunk of 8 elemnts). In other words, A1 and A2 should include the follwing elemnts of vector A:
A1=[A(1:16), A(25:40), A(49:64), etc]
A2=[A(17:24), A(41:48), A(65:72), etc]

Accepted Answer

Yongjian Feng
Yongjian Feng on 22 Jul 2021
Do it in a loop. Loop through 1 to 1000. Append elements to A1 and A2 inside the loop.
Yongjian Feng
Yongjian Feng on 22 Jul 2021
Try this:
A = [1:1000];
A1 = [];
A2 = [];
i = 1;
while i < length(A)
A1 = [A1 A(i:i+15)];
A2 = [A2 A(i+16:min(i+23, 1000))];
i = i+24;

Sign in to comment.

More Answers (0)


Find more on Loops and Conditional Statements in Help Center and File Exchange



Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!