How to shift all the non-zero elements of a matrix to the right of the matrix?

I have a matrix like

1 2 3 0 0 1 2 0

0 0 1 2 3 0 0 0

1 0 0 1 2 3 1 2

I want to shift all the non-zero elements to the right of the matrix. The answer should be

0 0 0 1 2 3 1 2

0 0 0 0 0 1 2 3

0 0 1 1 2 3 1 2

[Dyuman Joshi]

What have you tried yet?

Answer 1

[Adam Danz]

m = [1 2 3 0 0 1 2 0
     0 0 1 2 3 0 0 0
     1 0 0 1 2 3 1 2];
 
mSort = cell2mat(cellfun(@(v){[v(v==0),v(v~=0)]},mat2cell(m,ones(size(m,1),1),size(m,2))))

mSort = 3×8

0 0 0 1 2 3 1 2 0 0 0 0 0 1 2 3 0 0 1 1 2 3 1 2

Answer 2

[the cyclist]

% The original data
M = [1 2 3 0 0 1 2 0
     0 0 1 2 3 0 0 0
     1 0 0 1 2 3 1 2];

% Preallocate the matrix (which also effectively fills in all the zeros)
M_sorted = zeros(size(M));

% For each row of M, identify the non-zero elements, and fill them into the
% end of each corresponding row
for nm = 1:size(M,1)
    nonZeroThisRow = M(nm,M(nm,:)~=0);
    M_sorted(nm,end-numel(nonZeroThisRow)+1:end) = nonZeroThisRow;
end

% Display the result
disp(M_sorted)

     0     0     0     1     2     3     1     2
     0     0     0     0     0     1     2     3
     0     0     1     1     2     3     1     2

Answer 3

[Sean de Wolski]

Without loop or cells:

x = [1 2 3 0 0 1 2 0
    0 0 1 2 3 0 0 0
    1 0 0 1 2 3 1 2];
xt = x.';
sxr = sort(logical(xt), 1, "ascend");
[row, col] = find(sxr);
m = accumarray([col row], nonzeros(xt), size(x))

m = 3×8

0 0 0 1 2 3 1 2 0 0 0 0 0 1 2 3 0 0 1 1 2 3 1 2

[Adam Danz]

+1 nice one!