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How to use fmincon with vectors? (error message: not enough input arguments)

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I am trying to use fmincon to find values that maximizes the function. (2 variables)
The document on the website provides sample that provides scalar and I want to return vectors instead of it.
Below is the sample code I wrote to understand how fmincon works.
test = [1 2 3 4];
fun = @(c,d)100*(c-d^2)^2 + (test(:)-c).^2;
lb = [0,0.2,0,0.2 ; 0,0.2,0,0.2];
ub = [0.5,0.8,0.5,0.8 ; 0.5,0.8,0.5,0.8];
A = [];
b = [];
Aeq = [];
beq = [];
x0 = [1/4,1/4,1/4,1/4 ; 1/4,1/4,1/4,1/4 ];
[x,val] = fmincon(fun,x0,A,b,Aeq,beq,lb,ub)
So basically, I want to have (c,d) that maximizes fun for each value in test.
But when I run this code, it says 'Not enough input arguments'.
Seems like I made some mistake but couldn't find it.
Any help? Thanks in advance.

Accepted Answer

Matt J
Matt J on 6 Apr 2021
Edited: Matt J on 6 Apr 2021
fun = @(x) -100*(x(1,:)-x(2,:).^2).^2 + (test-x(1,:)).^2;
Chang seok Ma
Chang seok Ma on 6 Apr 2021
So if the problem is not additively separable, is there other way I could solve this problem without loop?
Matt J
Matt J on 6 Apr 2021
Edited: Matt J on 6 Apr 2021
If the problem weren't separable, using a loop would not be an option. You would be forced to solve it as an 8D minimization problem.

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