Curve-fitting part of a data set
5 views (last 30 days)
Show older comments
I need to use the polyfit command to determine the best fitting exponential for the time roughly between 1.7 and 2.25. I'm given the equation Temp(t) = Temp0 * exp(-(t-t0)/tau), where t0 is the time corresponding to temperature Temp0 (I can select where to begin my curve-fitting, but it is confined to the area roughly between 1.7 and 2.3). Here is my attempt.
%'time' vector ranges from 1.5 to 2.5
p = polyfit(time, log(Temp), 1);
%Arbitrary starting point
t0 = 1.71;
tau = -1./p(1)
Temp0 = exp(p(2))
tp = 1.7:0.01:2.3;
Temp_t = Temp0*exp(-(tm-t0)/tau);
plot(time, Temp, tp, Temp_t)
My curve ends up looking like this http://s7.postimg.org/igces77pn/temp2.jpg What am I doing incorrectly? How can I align the curve-fit line and the data points. I am told that circshift may help, but I couldn't grasp the function of the command after reading the help file. Any help would be greatly appreciated. Thank you!
0 Comments
Answers (1)
David Sanchez
on 27 May 2013
If I am not wrong, you are doing this:
% tau = -1./p(1)
% Temp0 = exp(p(2))
% Temp_t = Temp0*exp(-(tm-t0)/tau); % ->
% Temp_t = exp(p(2))*exp((tm-t0)*p(1)); % ->
Temp_t = exp( p(2)+(tm-t0)*p(1) );
Instead, I think you should just grab your Temp amd time data in your region of interest (1.7 to 2.3) taking care on grabbing an Temp/time array with the same length than your tp array. Then:
p = polyfit(time, Temp, 1);
Temp_p = p(1)*tp + p(2);
plot(time, Temp, tp, Temp_t)
0 Comments
See Also
Categories
Find more on Structures in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!